For a third degree monic polynomial, it is seen that the sum

for-a-third-degree-monic-polynomial-it-is-seen-that-the-sum

For a third degree monic polynomial, it is seen that the sum of roots are zero. What is the relation between the minimum angle to be rotated to have a Rolles point (α in Radians) and the cyclic sum of the roots taken two at a time c

A. α = ^π⁄180 * tan^-1C.

B. Can never have a Rolles point

C. α = ^180⁄π tan^-1C.

D. α = tan^-1C.

The question was asked in an online interview.

Query is from Lagrange’s Mean Value Theorem in division Differential Calculus of Engineering Mathematics

Right choice is D. α = tan^-1C.

For explanation I would say: From Vietas formulas we can deduce that the x^2 coefficient of the monic polynomial is zero (Sum of roots = zero). Hence, we can rewrite our third degree polynomial as

y = x^3 + (0) * x^2 + c * x + d

Now the question asks us to relate α and c

Where c is indeed the cyclic sum of two roots taken at a time by Vietas formulae

As usual, Rolles point in the rotated domain equals the Lagrange point in the existing domain. Hence, we must have

y ^‘ = tan(α)

3x^2 + c = tan(α)

To find the minimum angle, we have to find the minimum value of α

 such that the equation formed above has real roots when solved for x.

So, we can write

tan(α) – c > 0

tan(α) > c

α > tan^-1C.

Thus, the minimum required angle is

α = tan^-1C..