7(i)+ B(OCH3)3 → NaBH4 + 6(ii)+ 3(iii) Name the compounds i,

7-i-b-och3-3-nabh4-6-ii-3-iii-name-the-compounds-i

7(i)+ B(OCH3)3  → NaBH4 + 6(ii)+ 3(iii) Name the compounds i, ii, iii?

A. i.sodium hydride ii.sodium iii.methanol

B. i.sodium Ii.methanol iii.sodium hydride

C. i.sodium ii.sodium hydride iii.methanol

D. i.sodium hydride ii.methanol iii.sodium

This question was addressed to me in an interview for job.

This key question is from Inorganic Chemical in portion Inorganic Chemical Industries of Chemical Technology

Right choice is A. i.sodium hydride ii.sodium iii.methanol

To elaborate: The reaction is  7NaH + B(OCH3)3  → NaBH4 + 6Na + 3CH3OH, hence compound i is sodium hydride, compound ii is sodium and compound iii is methanol.