1 Faraday = _______________ A. 1 coulomb B. 1000 coulomb C. 5000

1-faraday-a-1-coulomb-b-1000-coulomb-c-5000

1 Faraday = _______________

A. 1 coulomb

B. 1000 coulomb

C. 5000 coulomb

D. 96500 coulomb

I got this question in final exam.

Query is from Faraday’s Laws of Electrolysis topic in chapter Corrosion, Electrolysis, Fuel Cells and Batteries of Engineering Chemistry II

The correct answer is D. 96500 coulomb

The best I can explain: 1 Faraday = 96,500 Coulomb. It is calculated mathematically and is widely used everywhere.