How does the capacitance change with the effect of the dielectric when the battery is kept disconnected from the capacitor?
A. Increases
B. Decreases
C. Remains constant
D. Zero
I got this question in homework.
Query is from Effect of Dielectric on Capacitance topic in chapter Electrostatic Potential and Capacitance of Physics – Class 12
Right answer is A. Increases
For explanation: When the battery is disconnected, and a dielectric is introduced, there will be a decrease in potential difference and as a result, the capacitance increases k times.
C = \(\frac {Q_0}{V}\)
C = \( [ \frac {Q_0}{(\frac {V_0}{k})} ] \)
C = \(\frac {kQ_0}{V_0}\)
C = kC0.