In a cyclotron, a magnetic induction of 1.4 T is used to accelerate protons. How rapidly should the electric field between the dees be reversed?
A. 5.2 × 10^-8 s
B. 2.34 × 10^-8 s
C. 792.25 × 10^-8 s
D. 46.25 × 10^-8 s
I got this question in unit test.
My question is from Motion in Combined Electric and Magnetic Field in section Moving Charges and Magnetism of Physics – Class 12
The correct answer is B. 2.34 × 10^-8 s
The best I can explain: Time period, t = \(\frac {\pi m}{qB}\)
t = \(\frac {(3.14 \, \times 1.67 \, \times \, 10^{-27})}{(1.6 \, \times \, 10^{-19} \, \times \, 1.4)}\)
t = 2.34 × 10^-8 s