Berapakah jarak antara titiik dan lingkaran berikut?
(8, -7) dan x2 + y2 – 4x – 2y – 31 = 0
Jawab:
x2 + y2 – 4x – 2y – 31 = 0
Pusat: (-½ (-4), (-½ (-2)) = (2, 1)
Jarak = 10 – 6 = 4
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Berapakah jarak antara titiik dan lingkaran berikut?
(8, -7) dan x2 + y2 – 4x – 2y – 31 = 0
Jawab:
x2 + y2 – 4x – 2y – 31 = 0
Pusat: (-½ (-4), (-½ (-2)) = (2, 1)
Jarak = 10 – 6 = 4
—————-#—————-